A man stands on a weighing machine kept inside a lift. Initially the lift is ascending with the acceleration ‘a’ due to which the reading is W. Now the lift descends with the same acceleration and reading is 10 % of initial. Find the acceleration of lift?
A
m/ sec 2
B
m/sec 2
C
0 m/ sec 2
D
g m/ sec 2
Text Solution
Verified by ExpertsThe correct answer is:
B
N = m (g + a)
N` = m (g - a)
N` = 
m (g – a) = 
10g – 10a = g + a
9g = 11a
a = 
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